-16t^2+60t+2=44

Solution for -16t^2+60t+2=44 equation:

-16t^2+60t+2=44

We move all terms to the left:

-16t^2+60t+2-(44)=0

We add all the numbers together, and all the variables

-16t^2+60t-42=0

a = -16; b = 60; c = -42;
Δ = b2-4ac
Δ = 602-4·(-16)·(-42)
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{57}}{2*-16}=\frac{-60-4\sqrt{57}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{57}}{2*-16}=\frac{-60+4\sqrt{57}}{-32}
$